the spring constant (k) is ... 20 N / (40 - 24) cm = 1.25 N/cm = 125 N/m
work = 1/2 k x^2 = 1/2 * 125 * [(.32 - .24) m]^2 = ? Joules
A spring has a natural length of 24 cm. If a 20-N force is required to keep it stretched to a length of 40 cm, how much work W is required to stretch it from 24 cm to 32 cm? (Round your answer to two decimal places.
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