Question

How many kJ of heat are required to convert 1.00 g of ice at -25°C to steam at 125°C?
s(ice) = 2.108 J/g·°C
s(liquid water) = 4.184 J/g·°C
s(steam) = 1.996 J/g·°C
heat of fusion = 6.01 kJ/mol
heat of vaporization = 40.79 kJ/mol
bobpursley
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