Asked by Anonymous
For the functions f(x) = sin x, show with the aid of the elementary formula sin^2 A = 1/2(1-cos 2A) that f(x+y) - f(x) = cos x sin y-2 sin x sin^2 (1/2y).
Answers
Answered by
Reiny
f(x) = sinx
then ...
f(x+y) - f(x)
= sin(x+y) - sinx
= sinxcosy + cosxsiny - sinx
= sinx(cosy - 1) + cosxsiny , ---- we need the cosxsiny in our final result, ok so far
= - sinx(1 - cosy) + cosxsiny
aside: from sin^2 A = 1/2(1-cos 2A)
sin^2 (y/2) = 1/2(1 - cosy)
2sin^2 (y/2) = 1 - cosy <----- we have that in our last step above
so from
- sinx(1 - cosy) + cosxsiny
= -sinx(2sin^2 (y/2) + cosxsiny
= cosxsiny - 2sinx(sin^2 (y/2))
= RS
QED
then ...
f(x+y) - f(x)
= sin(x+y) - sinx
= sinxcosy + cosxsiny - sinx
= sinx(cosy - 1) + cosxsiny , ---- we need the cosxsiny in our final result, ok so far
= - sinx(1 - cosy) + cosxsiny
aside: from sin^2 A = 1/2(1-cos 2A)
sin^2 (y/2) = 1/2(1 - cosy)
2sin^2 (y/2) = 1 - cosy <----- we have that in our last step above
so from
- sinx(1 - cosy) + cosxsiny
= -sinx(2sin^2 (y/2) + cosxsiny
= cosxsiny - 2sinx(sin^2 (y/2))
= RS
QED
Answered by
yuki
Reiny, how does cosy become cosy-1?
Answered by
Jon
why is it 2sin^2 y/2 and not sin^2 y/2?
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