Question

What mass (g) of Na2CO3 would be needed to react with 0.250 moles of HCI according to the equation
Na2CO3 + 2HCI ---> 2NaCI + CO2 + H2O.

My answer is 13.2g but I'm not sure if it is correct. Can someone please verify this for me. Any help is very much appreciated. Thanks

Answer 1

each mole of Na2CO3 reacts with 2 moles of HCl.
0.250/2 = 0.125 moles Na2CO3 = 13.25g
So, you are correct.

Answer 2

Thanks for checking