Asked by Tom
how am I supposed to graph 1.25+.25x and .50x
Answers
Answered by
henry2,
Y = 0.25x + 1.25.
Y = x/4 + 5/4
4y = x + 5
Eq1: x-4y = -5. standard form.
Graph: P1(3, 2), P2(5, 2.5).
Eq2: Y = 0.5x.
Graph: P1(0, 0), P2(2, 1).
The point where the lines intersect is the solution.
t
Y = x/4 + 5/4
4y = x + 5
Eq1: x-4y = -5. standard form.
Graph: P1(3, 2), P2(5, 2.5).
Eq2: Y = 0.5x.
Graph: P1(0, 0), P2(2, 1).
The point where the lines intersect is the solution.
t
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