Sure, I can help you with that! To graph a line with a given y-intercept and an ordered pair, you'll need to understand a few basic principles.
For Line 1, you're given the y-intercept of 3 and the ordered pair (3, 4). The y-intercept is the point where the line crosses the y-axis, so in this case, it would be a point on the graph with the coordinates (0, 3).
To plot the ordered pair (3, 4), you start at the origin, move 3 units up (since the y-coordinate is 4), and then move 3 units to the right (since the x-coordinate is 3). Once you arrive at this point, mark it on your graph.
Now, to draw the line, you can simply connect the y-intercept (0, 3) and the ordered pair (3, 4) with a straight line. This line represents the equation of Line 1.
Moving on to Line 2, the equation given is y = -2x + 2. This equation is in slope-intercept form, y = mx + b, where m represents the slope of the line and b represents the y-intercept.
In this case, the slope is -2, and the y-intercept is 2. This means that the line will have a slope of -2 (which can be thought of as "rise over run") and crosses the y-axis at the point (0, 2).
To graph Line 2, start at the y-intercept point (0, 2). From there, use the slope of -2 to plot additional points. For example, you can move 1 unit to the right (since the slope tells us the run is 1) and then move 2 units down (since the slope tells us the rise is -2).
Repeat this process to plot a couple more points, and then connect them with a straight line. This line represents the equation of Line 2.
I hope this helps you graph the given lines! Let me know if you have any further questions.