Question

i have one more question, and i hope someone can help with this, because im absolutely lost for this one.:
write the equation of a line that is perpendicular to the given line and passes through the given point.
y+2 = 1/3(x-5) ; (-4, 3)


i am so confused plz help

Answer 1

yummm ... tacos

perpendicular lines have slopes that are negative-reciprocals

the negative-reciprocal of 1/3 is -3

use point-slope to write the equation of the new line

Answer 2

so is it y= -3x +15?

Answer 3

or is it y= -1/3x -11

Answer 4

point-slope ... y - 3 = -3 (x - -4)

Answer 5

but it doesnt say to use point slope?

Answer 6

okay ... so which of your answers is correct?

Answer 7

y+2 = 1/3(x-5), (-4, 3).
3y+6 = x-5
Eq1: -x+3y = -11. slope = -A/B = 1/3.

Eq2 slope = -3.
y = mx+b.
3 = -3(-4) + b
b = -9.

Eq2: Y = -3x - 9.