Asked by Mariam
In a certain examination, 52 candidates offered biology, 60 history, 96 offered mathhematics , 21 offered biology and history, 22 offered both biology and mathematics, 16 mathematics and history. If 7 candidates offer all the three subjects find:(a) how many candidates were there for the examination
Answers
Answered by
Reiny
number(biology OR history OR mathematics) =
number(biology) + number(history) + number(math) - number(history ANS biology) - number(history AND math) - number(biology AND math) + number(biology AND history AND mathematics)
you are given each of those values, just plug in and evaluate.
number(biology) + number(history) + number(math) - number(history ANS biology) - number(history AND math) - number(biology AND math) + number(biology AND history AND mathematics)
you are given each of those values, just plug in and evaluate.
Answered by
oobleck
Using what you know about the intersections of sets, and using a Venn diagram, you can see that
(52+60+96)-(21+22+16)+(7) = 156
(52+60+96)-(21+22+16)+(7) = 156
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