Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A 89.0 kg person stands on one leg and 90% of the weight is supported by the upper leg connecting the knee and hip joint-the fe...Asked by James
A 89.0 kg person stands on one leg and 90% of the weight is supported by the upper leg connecting the knee and hip joint-the femur. Assuming the femur is 0.640 m long and has a radius of 1.90 cm, by how much is the bone compressed?
weight supported by femur=0.9(85.0kg)= 76.5kg
L= 0.650m
A=(pi)(0.02m)^2=0.1256m
femur bone radius=2.0cm=0.020m
thats how far i got
weight supported by femur=0.9(85.0kg)= 76.5kg
L= 0.650m
A=(pi)(0.02m)^2=0.1256m
femur bone radius=2.0cm=0.020m
thats how far i got