Question
Multiple Choice
What is the simplified form of 3 a superscript 4 baseline b superscript negative 2 baseline c superscript 3 baseline question mark
A. Start Fraction 81 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
B. Start Fraction 81 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
C. Start Fraction 3 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
D. Start Fraction 3 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
My guess is D.....
What is the simplified form of 3 a superscript 4 baseline b superscript negative 2 baseline c superscript 3 baseline question mark
A. Start Fraction 81 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
B. Start Fraction 81 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
C. Start Fraction 3 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
D. Start Fraction 3 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
My guess is D.....
Answers
Emo princess :3
1.d
2.c
3.d
4.a
5.a
2.c
3.d
4.a
5.a
Katelyn
TYSM EMO!!!! 100%!!!
oobleck
I agree, but you will find it much easier to write
(3^4 c^3)/b^2
And I know I'll find it much muchj easier to read!
(3^4 c^3)/b^2
And I know I'll find it much muchj easier to read!
DDM
This is so helpful thanks!
UwU
Emo princess :3 thank you are right!
Connexus
Thank you Emo princess
Sam
Emo's anwsers didnt work i got 1/5
FieryRose
3.6.4 - Practice: Properties of Exponents Online Practice
_____________________________________________
|1.| B. y^7
|2.| B. y^4
|3.| D. 1/125
|4.| B. 1
|5.| A. (y^2) (y^2), B. y^6/y^2, D. y^9/y^5
Thats all!~ ^w^
_____________________________________________
|1.| B. y^7
|2.| B. y^4
|3.| D. 1/125
|4.| B. 1
|5.| A. (y^2) (y^2), B. y^6/y^2, D. y^9/y^5
Thats all!~ ^w^
Iris gaming
FieryRose is correct not emo princess
Ellie
Emo princess :3 - All of the answers are wrong do not trust them, I got 0/5.
???
no its 100^20
???
no typo meant 100^96
anduin wrynn
emo's answers are for 9th grade connexus only.
i know just got 5/5 from her answers and i am on connexus.
i know just got 5/5 from her answers and i am on connexus.
Write the value of the expression.
Start Fraction 4 superscript 5 baseline over 4 superscript 5 baseline End Fraction
Start Fraction 4 superscript 5 baseline over 4 superscript 5 baseline End Fraction
Bot
The value of the expression is 1.
Any number raised to the power of itself equals 1.
Any number raised to the power of itself equals 1.
Start Fraction 2 squared over 2 superscript 5 baseline End Fraction
Bot
Start Fraction 2 squared over 2 superscript 5 baseline End Fraction can be simplified as follows:
2 squared is equal to 2 raised to the power of 2, which is 4.
2 raised to the power of 5 is 32.
Therefore, Start Fraction 2 squared over 2 superscript 5 baseline End Fraction = 4/32 = 1/8.
2 squared is equal to 2 raised to the power of 2, which is 4.
2 raised to the power of 5 is 32.
Therefore, Start Fraction 2 squared over 2 superscript 5 baseline End Fraction = 4/32 = 1/8.
Multiply. Write the result in scientific notation.
(1.8 • 10^1)(7 • 10^5)
(1.8 • 10^1)(7 • 10^5)
Bot
To multiply two numbers in scientific notation, we multiply their coefficients and add their exponents of 10.
(1.8 • 10^1)(7 • 10^5) = (1.8 * 7) * (10^1 * 10^5) = 12 * 10^6
Therefore, the result is 1.2 × 10^7 in scientific notation.
(1.8 • 10^1)(7 • 10^5) = (1.8 * 7) * (10^1 * 10^5) = 12 * 10^6
Therefore, the result is 1.2 × 10^7 in scientific notation.
(1.7 ∙ 10^–4)(5 ∙ 10^–5)
A. 8.5 ∙ 10^–9
B. 8.5 ∙ 10^20
C. 6.7 ∙ 10^–9
D. 6.7 ∙ 10^20
A. 8.5 ∙ 10^–9
B. 8.5 ∙ 10^20
C. 6.7 ∙ 10^–9
D. 6.7 ∙ 10^20
Bot
To multiply two numbers in scientific notation, we multiply their coefficients and add their exponents of 10.
(1.7 ∙ 10^–4)(5 ∙ 10^–5) = (1.7 * 5) * (10^–4 * 10^–5) = 8.5 × 10^-9
Therefore, the result is 8.5 ∙ 10^–9.
The answer is (A) 8.5 ∙ 10^–9.
(1.7 ∙ 10^–4)(5 ∙ 10^–5) = (1.7 * 5) * (10^–4 * 10^–5) = 8.5 × 10^-9
Therefore, the result is 8.5 ∙ 10^–9.
The answer is (A) 8.5 ∙ 10^–9.
Simplify the expression.
8t^5 ∙ 8t^5
8t^5 ∙ 8t^5
Bot
To simplify the expression, we multiply the coefficients and add the exponents of the variable t.
8t^5 ∙ 8t^5 = (8 * 8) * t^(5+5) = 64t^10
Therefore, the simplified expression is 64t^10.
8t^5 ∙ 8t^5 = (8 * 8) * t^(5+5) = 64t^10
Therefore, the simplified expression is 64t^10.
Simplify the expression.
–x(7x – 8)
–x(7x – 8)
Bot
To simplify the expression, we use distributive property of multiplication over addition/subtraction.
–x(7x – 8) = –x(7x) – (-x)(8) = –7x^2 + 8x
Therefore, the simplified expression is -7x^2 + 8x.
–x(7x – 8) = –x(7x) – (-x)(8) = –7x^2 + 8x
Therefore, the simplified expression is -7x^2 + 8x.
Simplify the expression.
3k^2(–2k^2 – 4k + 7)
3k^2(–2k^2 – 4k + 7)
Bot
To simplify the expression, we use distributive property of multiplication over addition/subtraction.
3k^2(–2k^2 – 4k + 7) = 3k^2 * -2k^2 + 3k^2 * -4k + 3k^2 * 7 = -6k^4 - 12k^3 + 21k^2
Therefore, the simplified expression is -6k^4 - 12k^3 + 21k^2.
3k^2(–2k^2 – 4k + 7) = 3k^2 * -2k^2 + 3k^2 * -4k + 3k^2 * 7 = -6k^4 - 12k^3 + 21k^2
Therefore, the simplified expression is -6k^4 - 12k^3 + 21k^2.
Simplify the expression.
(3k + 2)(k – 3)
(3k + 2)(k – 3)
Bot
To simplify this expression, we use the distributive property:
(3k + 2)(k – 3) = 3k(k – 3) + 2(k – 3)
Now we can distribute again and simplify:
= 3k^2 – 9k + 2k – 6
= 3k^2 – 7k – 6
Therefore, the simplified expression is 3k^2 – 7k – 6.
(3k + 2)(k – 3) = 3k(k – 3) + 2(k – 3)
Now we can distribute again and simplify:
= 3k^2 – 9k + 2k – 6
= 3k^2 – 7k – 6
Therefore, the simplified expression is 3k^2 – 7k – 6.
Note: For questions 22–23, your teacher will grade your response to ensure you receive proper credit for your answer.
Look at the given triangles.
triangles
The blue triangle is a right triangle. The vertical leg is labeled with the expression 4 x plus 2. The horizontal leg is labeled with the expression 5 x minus 4. The hypotenuse is labeled with the expression 7 x plus 7.
The red triangle is a right triangle. The vertical leg is labeled with the expression x plus 3. The horizontal leg is labeled with the expression x plus 7. The hypotenuse is labeled with the expression 2 x minus 5.
a. Write an expression in simplest form for the perimeter of each triangle.
b. Write another expression in simplest form that shows the difference between the perimeter of the larger triangle and the perimeter of the smaller triangle.
c. Find the perimeter for each triangle when x = 3
Look at the given triangles.
triangles
The blue triangle is a right triangle. The vertical leg is labeled with the expression 4 x plus 2. The horizontal leg is labeled with the expression 5 x minus 4. The hypotenuse is labeled with the expression 7 x plus 7.
The red triangle is a right triangle. The vertical leg is labeled with the expression x plus 3. The horizontal leg is labeled with the expression x plus 7. The hypotenuse is labeled with the expression 2 x minus 5.
a. Write an expression in simplest form for the perimeter of each triangle.
b. Write another expression in simplest form that shows the difference between the perimeter of the larger triangle and the perimeter of the smaller triangle.
c. Find the perimeter for each triangle when x = 3
Bot
a. To find the perimeter of each triangle, we add up the lengths of all three sides:
Perimeter of blue triangle = (4x + 2) + (5x - 4) + (7x + 7) = 16x + 5
Perimeter of red triangle = (x + 3) + (x + 7) + (2x - 5) = 4x + 5
b. The difference between the perimeter of the larger triangle and the perimeter of the smaller triangle can be found by subtracting the perimeter of the blue triangle from the perimeter of the red triangle:
(4x + 5) - (16x + 5) = -12x
Another way to write this expression is:
(16x + 5) - (4x + 5) = 12x
c. To find the perimeter of each triangle when x = 3, we substitute 3 for x in the expressions we found in part (a):
Perimeter of blue triangle = 16(3) + 5 = 53
Perimeter of red triangle = 4(3) + 5 = 17
Therefore, the perimeter of the blue triangle is 53 units and the perimeter of the red triangle is 17 units when x = 3.
Perimeter of blue triangle = (4x + 2) + (5x - 4) + (7x + 7) = 16x + 5
Perimeter of red triangle = (x + 3) + (x + 7) + (2x - 5) = 4x + 5
b. The difference between the perimeter of the larger triangle and the perimeter of the smaller triangle can be found by subtracting the perimeter of the blue triangle from the perimeter of the red triangle:
(4x + 5) - (16x + 5) = -12x
Another way to write this expression is:
(16x + 5) - (4x + 5) = 12x
c. To find the perimeter of each triangle when x = 3, we substitute 3 for x in the expressions we found in part (a):
Perimeter of blue triangle = 16(3) + 5 = 53
Perimeter of red triangle = 4(3) + 5 = 17
Therefore, the perimeter of the blue triangle is 53 units and the perimeter of the red triangle is 17 units when x = 3.
Emma, Erin, and Eden completed the problem to the right.
a. Who completed the problem correctly?
b. What did the other two students do wrong in their answers?
Emma's equation shows 6 squared times 6 superscript 5 baseline equals 36 superscript 7 baseline.
Erin's equation shows 6 squared times 6 superscript 5 baseline equals 6 superscript 10 baseline.
Eden's equation shows 6 squared times 6 superscript 5 baseline equals 6 superscript 7 baseline.
Bot
a. Emma completed the problem correctly.
b. Erin made a mistake with the exponent of 6. Instead of adding the exponents, she multiplied them and got 6^7, which is incorrect.
Eden also made a mistake with the exponent of 6. Instead of multiplying the coefficients and adding the exponents, she only added the exponents and got 6^7, which is incorrect.
b. Erin made a mistake with the exponent of 6. Instead of adding the exponents, she multiplied them and got 6^7, which is incorrect.
Eden also made a mistake with the exponent of 6. Instead of multiplying the coefficients and adding the exponents, she only added the exponents and got 6^7, which is incorrect.