Asked by Katelyn
Multiple Choice
What is the simplified form of 3 a superscript 4 baseline b superscript negative 2 baseline c superscript 3 baseline question mark
A. Start Fraction 81 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
B. Start Fraction 81 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
C. Start Fraction 3 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
D. Start Fraction 3 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
My guess is D.....
What is the simplified form of 3 a superscript 4 baseline b superscript negative 2 baseline c superscript 3 baseline question mark
A. Start Fraction 81 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
B. Start Fraction 81 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
C. Start Fraction 3 a superscript 4 baseline over b superscript 2 baseline c superscript 3 baseline End Fraction
D. Start Fraction 3 a superscript 4 baseline c superscript 3 baseline over b superscript 2 baseline End Fraction
My guess is D.....
Answers
Answered by
Emo princess :3
1.d
2.c
3.d
4.a
5.a
2.c
3.d
4.a
5.a
Answered by
Katelyn
TYSM EMO!!!! 100%!!!
Answered by
oobleck
I agree, but you will find it much easier to write
(3^4 c^3)/b^2
And I know I'll find it much muchj easier to read!
(3^4 c^3)/b^2
And I know I'll find it much muchj easier to read!
Answered by
DDM
This is so helpful thanks!
Answered by
UwU
Emo princess :3 thank you are right!
Answered by
Connexus
Thank you Emo princess
Answered by
Sam
Emo's anwsers didnt work i got 1/5
Answered by
FieryRose
3.6.4 - Practice: Properties of Exponents Online Practice
_____________________________________________
|1.| B. y^7
|2.| B. y^4
|3.| D. 1/125
|4.| B. 1
|5.| A. (y^2) (y^2), B. y^6/y^2, D. y^9/y^5
Thats all!~ ^w^
_____________________________________________
|1.| B. y^7
|2.| B. y^4
|3.| D. 1/125
|4.| B. 1
|5.| A. (y^2) (y^2), B. y^6/y^2, D. y^9/y^5
Thats all!~ ^w^
Answered by
Iris gaming
FieryRose is correct not emo princess
Answered by
Ellie
Emo princess :3 - All of the answers are wrong do not trust them, I got 0/5.
Answered by
???
no its 100^20
Answered by
???
no typo meant 100^96
Answered by
anduin wrynn
emo's answers are for 9th grade connexus only.
i know just got 5/5 from her answers and i am on connexus.
i know just got 5/5 from her answers and i am on connexus.
Answer
Write the value of the expression.
Start Fraction 4 superscript 5 baseline over 4 superscript 5 baseline End Fraction
Start Fraction 4 superscript 5 baseline over 4 superscript 5 baseline End Fraction
Answer
Start Fraction 2 squared over 2 superscript 5 baseline End Fraction
Answer
Multiply. Write the result in scientific notation.
(1.8 • 10^1)(7 • 10^5)
(1.8 • 10^1)(7 • 10^5)
Answer
(1.7 ∙ 10^–4)(5 ∙ 10^–5)
A. 8.5 ∙ 10^–9
B. 8.5 ∙ 10^20
C. 6.7 ∙ 10^–9
D. 6.7 ∙ 10^20
A. 8.5 ∙ 10^–9
B. 8.5 ∙ 10^20
C. 6.7 ∙ 10^–9
D. 6.7 ∙ 10^20
Answer
Simplify the expression.
8t^5 ∙ 8t^5
8t^5 ∙ 8t^5
Answer
Simplify the expression.
–x(7x – 8)
–x(7x – 8)
Answer
Simplify the expression.
3k^2(–2k^2 – 4k + 7)
3k^2(–2k^2 – 4k + 7)
Answer
Simplify the expression.
(3k + 2)(k – 3)
(3k + 2)(k – 3)
Answer
Note: For questions 22–23, your teacher will grade your response to ensure you receive proper credit for your answer.
Look at the given triangles.
triangles
The blue triangle is a right triangle. The vertical leg is labeled with the expression 4 x plus 2. The horizontal leg is labeled with the expression 5 x minus 4. The hypotenuse is labeled with the expression 7 x plus 7.
The red triangle is a right triangle. The vertical leg is labeled with the expression x plus 3. The horizontal leg is labeled with the expression x plus 7. The hypotenuse is labeled with the expression 2 x minus 5.
a. Write an expression in simplest form for the perimeter of each triangle.
b. Write another expression in simplest form that shows the difference between the perimeter of the larger triangle and the perimeter of the smaller triangle.
c. Find the perimeter for each triangle when x = 3
Look at the given triangles.
triangles
The blue triangle is a right triangle. The vertical leg is labeled with the expression 4 x plus 2. The horizontal leg is labeled with the expression 5 x minus 4. The hypotenuse is labeled with the expression 7 x plus 7.
The red triangle is a right triangle. The vertical leg is labeled with the expression x plus 3. The horizontal leg is labeled with the expression x plus 7. The hypotenuse is labeled with the expression 2 x minus 5.
a. Write an expression in simplest form for the perimeter of each triangle.
b. Write another expression in simplest form that shows the difference between the perimeter of the larger triangle and the perimeter of the smaller triangle.
c. Find the perimeter for each triangle when x = 3
Answer
Emma, Erin, and Eden completed the problem to the right.
a. Who completed the problem correctly?
b. What did the other two students do wrong in their answers?
Emma's equation shows 6 squared times 6 superscript 5 baseline equals 36 superscript 7 baseline.
Erin's equation shows 6 squared times 6 superscript 5 baseline equals 6 superscript 10 baseline.
Eden's equation shows 6 squared times 6 superscript 5 baseline equals 6 superscript 7 baseline.
Answered by
Bot
The value of the expression is 1.
Any number raised to the power of itself equals 1.
Any number raised to the power of itself equals 1.
Answered by
Bot
Start Fraction 2 squared over 2 superscript 5 baseline End Fraction can be simplified as follows:
2 squared is equal to 2 raised to the power of 2, which is 4.
2 raised to the power of 5 is 32.
Therefore, Start Fraction 2 squared over 2 superscript 5 baseline End Fraction = 4/32 = 1/8.
2 squared is equal to 2 raised to the power of 2, which is 4.
2 raised to the power of 5 is 32.
Therefore, Start Fraction 2 squared over 2 superscript 5 baseline End Fraction = 4/32 = 1/8.
Answered by
Bot
To multiply two numbers in scientific notation, we multiply their coefficients and add their exponents of 10.
(1.8 • 10^1)(7 • 10^5) = (1.8 * 7) * (10^1 * 10^5) = 12 * 10^6
Therefore, the result is 1.2 × 10^7 in scientific notation.
(1.8 • 10^1)(7 • 10^5) = (1.8 * 7) * (10^1 * 10^5) = 12 * 10^6
Therefore, the result is 1.2 × 10^7 in scientific notation.
Answered by
Bot
To multiply two numbers in scientific notation, we multiply their coefficients and add their exponents of 10.
(1.7 ∙ 10^–4)(5 ∙ 10^–5) = (1.7 * 5) * (10^–4 * 10^–5) = 8.5 × 10^-9
Therefore, the result is 8.5 ∙ 10^–9.
The answer is (A) 8.5 ∙ 10^–9.
(1.7 ∙ 10^–4)(5 ∙ 10^–5) = (1.7 * 5) * (10^–4 * 10^–5) = 8.5 × 10^-9
Therefore, the result is 8.5 ∙ 10^–9.
The answer is (A) 8.5 ∙ 10^–9.
Answered by
Bot
To simplify the expression, we multiply the coefficients and add the exponents of the variable t.
8t^5 ∙ 8t^5 = (8 * 8) * t^(5+5) = 64t^10
Therefore, the simplified expression is 64t^10.
8t^5 ∙ 8t^5 = (8 * 8) * t^(5+5) = 64t^10
Therefore, the simplified expression is 64t^10.
Answered by
Bot
To simplify the expression, we use distributive property of multiplication over addition/subtraction.
–x(7x – 8) = –x(7x) – (-x)(8) = –7x^2 + 8x
Therefore, the simplified expression is -7x^2 + 8x.
–x(7x – 8) = –x(7x) – (-x)(8) = –7x^2 + 8x
Therefore, the simplified expression is -7x^2 + 8x.
Answered by
Bot
To simplify the expression, we use distributive property of multiplication over addition/subtraction.
3k^2(–2k^2 – 4k + 7) = 3k^2 * -2k^2 + 3k^2 * -4k + 3k^2 * 7 = -6k^4 - 12k^3 + 21k^2
Therefore, the simplified expression is -6k^4 - 12k^3 + 21k^2.
3k^2(–2k^2 – 4k + 7) = 3k^2 * -2k^2 + 3k^2 * -4k + 3k^2 * 7 = -6k^4 - 12k^3 + 21k^2
Therefore, the simplified expression is -6k^4 - 12k^3 + 21k^2.
Answered by
Bot
To simplify this expression, we use the distributive property:
(3k + 2)(k – 3) = 3k(k – 3) + 2(k – 3)
Now we can distribute again and simplify:
= 3k^2 – 9k + 2k – 6
= 3k^2 – 7k – 6
Therefore, the simplified expression is 3k^2 – 7k – 6.
(3k + 2)(k – 3) = 3k(k – 3) + 2(k – 3)
Now we can distribute again and simplify:
= 3k^2 – 9k + 2k – 6
= 3k^2 – 7k – 6
Therefore, the simplified expression is 3k^2 – 7k – 6.
Answered by
Bot
a. To find the perimeter of each triangle, we add up the lengths of all three sides:
Perimeter of blue triangle = (4x + 2) + (5x - 4) + (7x + 7) = 16x + 5
Perimeter of red triangle = (x + 3) + (x + 7) + (2x - 5) = 4x + 5
b. The difference between the perimeter of the larger triangle and the perimeter of the smaller triangle can be found by subtracting the perimeter of the blue triangle from the perimeter of the red triangle:
(4x + 5) - (16x + 5) = -12x
Another way to write this expression is:
(16x + 5) - (4x + 5) = 12x
c. To find the perimeter of each triangle when x = 3, we substitute 3 for x in the expressions we found in part (a):
Perimeter of blue triangle = 16(3) + 5 = 53
Perimeter of red triangle = 4(3) + 5 = 17
Therefore, the perimeter of the blue triangle is 53 units and the perimeter of the red triangle is 17 units when x = 3.
Perimeter of blue triangle = (4x + 2) + (5x - 4) + (7x + 7) = 16x + 5
Perimeter of red triangle = (x + 3) + (x + 7) + (2x - 5) = 4x + 5
b. The difference between the perimeter of the larger triangle and the perimeter of the smaller triangle can be found by subtracting the perimeter of the blue triangle from the perimeter of the red triangle:
(4x + 5) - (16x + 5) = -12x
Another way to write this expression is:
(16x + 5) - (4x + 5) = 12x
c. To find the perimeter of each triangle when x = 3, we substitute 3 for x in the expressions we found in part (a):
Perimeter of blue triangle = 16(3) + 5 = 53
Perimeter of red triangle = 4(3) + 5 = 17
Therefore, the perimeter of the blue triangle is 53 units and the perimeter of the red triangle is 17 units when x = 3.
Answered by
Bot
a. Emma completed the problem correctly.
b. Erin made a mistake with the exponent of 6. Instead of adding the exponents, she multiplied them and got 6^7, which is incorrect.
Eden also made a mistake with the exponent of 6. Instead of multiplying the coefficients and adding the exponents, she only added the exponents and got 6^7, which is incorrect.
b. Erin made a mistake with the exponent of 6. Instead of adding the exponents, she multiplied them and got 6^7, which is incorrect.
Eden also made a mistake with the exponent of 6. Instead of multiplying the coefficients and adding the exponents, she only added the exponents and got 6^7, which is incorrect.
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