Asked by marta

factor polynomial using difference or sum of cubes


64x^6 - h^6


please with baby steps

thank you!
Answered by oobleck
64x^6 - h^6
= (4x^2)^3 - (h^2)^3
= (4x^2-h^2)((4x)^2+(4x)(h^2)+(h^2)^2) = ...

note that 4x^2-h^2 can also be factored as the difference of squares.