Asked by Kamara
if (3-a) 6(2-5a) are conservative terms of a GP with common ratio r>0.
find the value of a
find the value of a
Answers
Answered by
Reiny
I will assume you meant to say:
3-a , 6, and 2-5a are <b>consecutive</b> terms of a GP,
(3-a)(2-5a) = 36
6 -17a + 5a^2 - 36 = 0
5a^2 - 17a - 30 = 0
a = (17 ± √889)/10
3-a , 6, and 2-5a are <b>consecutive</b> terms of a GP,
(3-a)(2-5a) = 36
6 -17a + 5a^2 - 36 = 0
5a^2 - 17a - 30 = 0
a = (17 ± √889)/10
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