Asked by Barry

A piece of gold-aluminium alloy weighs 49N when suspended from a spring balance and submerged in water it weighs 39.2N what is the weight of Gold in the alloy if the specific gravity of gold is 19.3 and aluminium is 2.5?

Answers

Answered by R_scott
specific gravity = 49 / (49 - 39.2)

(x * 19.3) + [(1 - x) * 2.5] = specific gravity

x is the fraction of the alloy that is gold
Answered by henry2,
19.3 + 2.5 = 21.8.

19.3/21.8*49 = 43.4 N. of gold.
49-43.4 = 5.6 N. of of aluminum.


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