Asked by Jonathan

While decorating her apartment, Julie pushes a 608-N dresser across the floor by applying a 578-N horizontal force. The coefficient of friction between the dresser and the floor is 0.745. Determine the magnitude of the acceleration (in m/s/s) of the dresser.
Answered by henry2,
u*Fn = = 0.745*608 = 453 N. = Force of friction.

M*g = 608.
M*9.8 = 608,
M = 62 kg.
.
FORCE APPLIED - FORCE OF FRICTION = M*a.
608-453 = M*a. = 62a.
a =
























There are no AI answers yet. The ability to request AI answers is coming soon!