Asked by Abdulwahid

A solid hass of 400g in air and partly immersed in a certain liquid it has a mass of 320kg .given that the relative density of the liquid is 0.80. Calculate the volume of the solid immersed in the liquid.
Answered by henry2,
400g-320g = 80 g. of liquid displaced.

D = 0.8 * Dw = 0.8 * 1g/cm^3 = 0.8g/cm^3. = Density of the liquid.
Dw = Density of water.

V*D = 80g.
V * 0.8 = 80,
V = 100 cm^3 = Vol. of liquid disp. = Vol. of the solid immersed.


Answered by Maxwell
An answer to my question
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