Question
A boy uses a rope to haul a box of weight 600N up an inclined wooden plane of effective length 3.0m and onto a platform 1.0m high. If in doing so, he exerts a force of 400N on the rope. Draw the diagram of all the forces acting on the box and calculate the frictional force between the box and the incline plane
Answers
sinA = 1m/3m = 0.333. A = 19.5o.
Fp = Mg*sinA = 600*sin19.5 = 200 N. = Force parallel with plane.
Fs = Force of static or starting friction.
Fe-Fp-Fs = M*a.
400-200-Fs = M*0 = 0,
Fs = 200 N.
Fp = Mg*sinA = 600*sin19.5 = 200 N. = Force parallel with plane.
Fs = Force of static or starting friction.
Fe-Fp-Fs = M*a.
400-200-Fs = M*0 = 0,
Fs = 200 N.
correct
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