Asked by Anonymous
The quantity y is partly constant and partly varies as the square of x. when x=1,y=11 and when x=2 ,y=5. Find the value of y when x =4
Answers
Answered by
oobleck
y = m + kx^2
You are told that
m + k = 11
m + 4k = 5
So, solve for m and k, and then plug in x=4
You are told that
m + k = 11
m + 4k = 5
So, solve for m and k, and then plug in x=4
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