Three "areas" ?
According to my diagram, I have triangle ABC, with angle B = 25°, BC=75 and AB = 53
direct case of cosine law:
AC^2 = 53^2 + 75^2 - 2(53)(75)cos25°
= ...
three areas A, B and C are such that B is 53 km on a bearing of 295 deg From A and C is 75 km east of B. Determine the distance in km, of C From A.
1 answer