Asked by Auwal rabiu dankoli

simplify cos2θ ÷ sinθ + cosθ
Answered by oobleck
There are lots of ways to massage this, but none really very simple...
cos2θ ÷ sinθ + cosθ
= (cos2θ + sinθ cosθ)/sinθ
= (2cos2θ + sin2θ)/(2sinθ)

Ahh. Maybe you meant
cos2θ ÷ (sinθ + cosθ)
= (cos^2θ - sin^2θ)/(cosθ + sinθ)
= cosθ - sinθ
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