Asked by ceaty
Suppose you have 12 coins that total 32 cents. Some of the coins are nickels and the rest are pennies. How many of each coin do you have?
Answers
Answered by
oobleck
add up the coins, and add up the values.
Now solve those two equations.
What do you get?
Now solve those two equations.
What do you get?
Answered by
John
p + n = 12 this represents the number of pennies and nickels.
.01 p + .05 n = .32 in this equation, you are getting the value of the coins.
The problem may be easier if you multiply the 2nd equation by 100
p + 5n = 32. finally use elimination to fine p and n by using the first equation and this equation. Hope that helps. Remember to check your answer to be sure that the number of coins adds to 12 and the value of the coins = 32 cents.
.01 p + .05 n = .32 in this equation, you are getting the value of the coins.
The problem may be easier if you multiply the 2nd equation by 100
p + 5n = 32. finally use elimination to fine p and n by using the first equation and this equation. Hope that helps. Remember to check your answer to be sure that the number of coins adds to 12 and the value of the coins = 32 cents.
Answered by
Anonymous
5 nickles. 7 penny's
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