my experience is formate calcium will form (Ca(HCO2)2 ) will formin that reaction. So I will play along and try to get CaCO3 (s) instead.
Wondering if you meant Ca(OH)2 solution.....
Assuming you did mean that
Ca(OH)2 + CO2 >>>Ca(CO3) + H2O
so moles, it is one to one on Ca(OH)2 vs Ca(CO3)
moles Ca(OH)2: .1*.25=.025 moles, so you form .025 moles calcum carbonate, which in grams is .025*(100)=2,5 grams
check my calculations
How many grams of caco3 will be formed by passing excess co2 gas through 100ml of 0.25M ca(H)2 solution?
1 answer