Asked by Trent
What is the equation of a circle with its center at (−6,−3) and a radius of 12?
A: (x−6)2+(y−3)2=12
B: (x−6)2+(y−3)2=144
C: (x+6)2+(y+3)2=144
D: (x+6)2+(y+3)2=12
E: (x+6)2+(y+3)2=24
I believe that it is C
A: (x−6)2+(y−3)2=12
B: (x−6)2+(y−3)2=144
C: (x+6)2+(y+3)2=144
D: (x+6)2+(y+3)2=12
E: (x+6)2+(y+3)2=24
I believe that it is C
Answers
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.