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What is the equation of a circle with its center at (−6,−3) and a radius of 12?
A: (x−6)2+(y−3)2=12
B: (x−6)2+(y−3)2=144
C: (x+6)2+(y+3)2=144
D: (x+6)2+(y+3)2=12
E: (x+6)2+(y+3)2=24

I believe that it is C
5 years ago

Answers

Trent
Also, the 2's after the parenthesis are supposed the be exponents
5 years ago
R_scott
I believe that you're correct
5 years ago

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