What is the equation of a circle with its center at (−6,−3) and a radius of 12?

Question

A: (x−6)2+(y−3)2=12
B: (x−6)2+(y−3)2=144
C: (x+6)2+(y+3)2=144
D: (x+6)2+(y+3)2=12
E: (x+6)2+(y+3)2=24

I believe that it is C

Answer 1

Also, the 2's after the parenthesis are supposed the be exponents

Answer 2

I believe that you're correct