Asked by dinaol
suppose a code of five characters,two letters followed by three digits. find
(a) codes
(b) codes with distinct letter
(c) codes with the same letters
(a) codes
(b) codes with distinct letter
(c) codes with the same letters
Answers
Answered by
Reiny
Looking at b), I will assume that in a) letters and digits may be repeated.
a) number of codes = 27*27*10*10*10 =
b) Distinct letters, but repeated digits : 27*26*10*10*10 =
distinct letter and distinct codes: 27*26*10*9*8 =
c) codes with same letters but distinct digits: 27*1*10*9*8 =
codes with the same letters and repeated digits : 27*1*10*10*10 =
codes with same letters and same digits: 27*1*10*1*1 = 27*10 =
a) number of codes = 27*27*10*10*10 =
b) Distinct letters, but repeated digits : 27*26*10*10*10 =
distinct letter and distinct codes: 27*26*10*9*8 =
c) codes with same letters but distinct digits: 27*1*10*9*8 =
codes with the same letters and repeated digits : 27*1*10*10*10 =
codes with same letters and same digits: 27*1*10*1*1 = 27*10 =
Answered by
Reiny
My mistake!!!!
There are 26 letters, not 27,
So make the necessary changes.
There are 26 letters, not 27,
So make the necessary changes.
Answered by
Muhammad Mohsin
Looking at b), I will assume that in a) letters and digits may be repeated.
a) number of codes = 26*26*10*10*10 = 676000
b) Distinct letters, but repeated digits : 26*25*10*10*10 =650000
distinct letter and distinct codes: 26*25*10*9*8 = 468000
c) codes with same letters but distinct digits: 26*1*10*9*8 =18720
codes with the same letters and repeated digits : 26*1*10*10*10 = 26000
codes with same letters and same digits: 26*1*10*1*1 = 26*10 =260
a) number of codes = 26*26*10*10*10 = 676000
b) Distinct letters, but repeated digits : 26*25*10*10*10 =650000
distinct letter and distinct codes: 26*25*10*9*8 = 468000
c) codes with same letters but distinct digits: 26*1*10*9*8 =18720
codes with the same letters and repeated digits : 26*1*10*10*10 = 26000
codes with same letters and same digits: 26*1*10*1*1 = 26*10 =260
Answered by
Nipu
A club has 25 members.(a) How many ways are there to choose four members of the club to
serve on an executive committee? (b) How many ways are there to choose a president, vice-
president, secretary, and treasurer of the club, where no person can hold more than one
office?
serve on an executive committee? (b) How many ways are there to choose a president, vice-
president, secretary, and treasurer of the club, where no person can hold more than one
office?
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