Asked by FS
When glucose-6-phosphate and fructose-6-phosphate are mixed with the enzyme phosphohexose isomerase under standard conditions, the final equilibrium concentration of glucose-6-phosphate is 1.33 M and the final concentration of fructose-6-phosphate is 0.66 M. What is the free energy change for the conversion of glucose-6-phosphate
→ fructose-6-phosphate?
The answer is deltaG=+ 1.7 kJ/mol
→ fructose-6-phosphate?
The answer is deltaG=+ 1.7 kJ/mol
Answers
Answered by
DrBob222
dG = -RTlnK
K = 0.66/1.33
R = 8.314
T = 298
dG = 1.7 kJ
K = 0.66/1.33
R = 8.314
T = 298
dG = 1.7 kJ
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