Asked by Morea
Four kids; Aaron, Bessy, Carli, and Dawn Play with beads. They start with 200 beads in all. Aaron gave Bessy 26 beats, Bessy gave Carli 36 beats, Carli gave Dawn 32 beads, and Dawn gave Aaron 4 beads. They end up with the same number of beads each other. How many beads did each of them have at the beginning?
Answers
Answered by
bcm
would it be 50 beads each
dont know if i'm right though
dont know if i'm right though
Answered by
nunya
what are the answer choices
Answered by
Morea
No answer choices, free answer sort of thing.
Answered by
Damon
Aaron has A - 26 + 4 = A - 22
Bessy has B + 26 - 36 = B -10
Carli has C +36 -32 = C + 4
Dawn has D +32 -4 = D + 28
A + B + C + D = 200 at start and at finish
A-22 = B - 10 = C+4 = D+28 = 200/4 = 50
so
A = 50 + 22
B = 50 + 10
C = 50 - 4
D = 50 - 28
luckily 22+10 - 2 - 28 is zero :)
Bessy has B + 26 - 36 = B -10
Carli has C +36 -32 = C + 4
Dawn has D +32 -4 = D + 28
A + B + C + D = 200 at start and at finish
A-22 = B - 10 = C+4 = D+28 = 200/4 = 50
so
A = 50 + 22
B = 50 + 10
C = 50 - 4
D = 50 - 28
luckily 22+10 - 2 - 28 is zero :)
Answered by
Damon
no nunya
A = 72
B = 60
C = 46
D = 22
A = 72
B = 60
C = 46
D = 22
Answered by
Morea
You just literally blew my mind! The answer is 0 then? I’m so stupid 😂
Answered by
Damon
No, the sum of changes is 0
the answer is
A = 72
B = 60
C = 46
D = 22
the answer is
A = 72
B = 60
C = 46
D = 22
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