Asked by Ace
Which equation shows p(x)=x6−1 factored completely over the integers? (Hint: You will need to use more than one method to complete this problem.)
p(x)=(x3+1)(x3−1)
p(x)=(x2−1)(x4+x2+1)
p(x)=(x−1)(x2+x+1)(x+1)(x2−x+1)
p(x)=(x−1)(x+1)(x4+x2+1)
p(x)=(x3+1)(x3−1)?
p(x)=(x3+1)(x3−1)
p(x)=(x2−1)(x4+x2+1)
p(x)=(x−1)(x2+x+1)(x+1)(x2−x+1)
p(x)=(x−1)(x+1)(x4+x2+1)
p(x)=(x3+1)(x3−1)?
Answers
Answered by
Chicken Nugget
For the people in the future, I just took the test and Ace's answer is right.
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