Asked by geechu
vector A has magnitude 8units and makes an agle of45°with the positive x-axis vector B also has the same magnitude of 8units and directed along the negative x-axis determine the magnitude and direction of A+B?
Answers
Answered by
bobpursley
Brake into components:
A=8cos45 x + 8 sin45 y
B=8cos 180x= -8 x
Now add A+B: (8cos45-8) x+ 8sin 45 y
A=8cos45 x + 8 sin45 y
B=8cos 180x= -8 x
Now add A+B: (8cos45-8) x+ 8sin 45 y
Answered by
amanuel
please,full answer
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Hareg
0910284517
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Tolesa
Abdi
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lelo
yuyuiyuiyuyukyui
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Nega Lema Lalimo
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Habtamu
There is no response
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Nasir Ahmed
Ahmed
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ASHU
FULL ANSNWER
Answered by
ASHU
Vector ⃗ has magnitude of 8units and makes an angle of 450 with the positive x-axis.
Vector ⃗⃗ also has the same magnitude of 8units and directed along the negative x-axis.
Find
a. The magnitude and direction of ⃗ ⃗⃗
b. The magnitude and direction of ⃗ ⃗⃗
Vector ⃗⃗ also has the same magnitude of 8units and directed along the negative x-axis.
Find
a. The magnitude and direction of ⃗ ⃗⃗
b. The magnitude and direction of ⃗ ⃗⃗
Answered by
ASHU
0983490131
Answered by
Yabsira
Good solution
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Henok Tadie
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