Asked by Anonymus
Explain how to solve: cos(arcsin√5/3)
Answers
Answered by
oobleck
In cases like this, always draw the triangle involved. You want cosx, where sinx = √5/3
So, the hypotenuse is 3, and the opposite leg is √5
The near leg is √(3^2-5) = √4 = 2
so, cosx = 2/3
So, the hypotenuse is 3, and the opposite leg is √5
The near leg is √(3^2-5) = √4 = 2
so, cosx = 2/3
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