1. c is right
Now find the other two,
A. 2/14, 3/21, 4/28
B. 1/8, 2/16, 3/24
C. 1/9, 2/18, 3/27*****my answer
D. 5/40, 5/45, 5/50***also kinda thinking about it
Jake sold 28 tickets to the school fair, and Jeanne sold 21 tickets. What is the ratio in simplest form, of the number of tickets Jeanne sold to the number of tickets Jake sold?
A. 3/4
B. 4/3
C. 28/21
D. 21/28****my answer
Now find the other two,
Simplify your answer to the second question.
First, let's simplify 5/40. We can divide both the numerator and denominator by their greatest common divisor (GCD) to simplify the fraction. In this case, the GCD of 5 and 40 is 5. Divide both by 5 to simplify:
5/40 = 1/8
Now we can find three ratios with the same simplified value:
A. 2/14 = 1/7
3/21 = 1/7
4/28 = 1/7
B. 1/8 = 1/8
2/16 = 1/8
3/24 = 1/8
C. 1/9 ≠1/8
2/18 ≠1/8
3/27 ≠1/8
D. 5/40 ≠1/8
5/45 ≠1/8
5/50 ≠1/8
Out of the given options, only option C. 1/9, 2/18, 3/27 equals 1/8, which is the simplified form of 5/40.
For the second question, we need to find the ratio of tickets sold by Jeanne to those sold by Jake in simplest form.
Given that Jake sold 28 tickets and Jeanne sold 21 tickets, the ratio of Jeanne's tickets to Jake's tickets can be calculated as follows:
Jeanne/Jake = 21/28
To simplify this ratio, we can divide both the numerator and denominator by their GCD. In this case, the GCD of 21 and 28 is 7. Divide both by 7 to get the simplified form:
Jeanne/Jake = 3/4
So, the correct answer is A. 3/4.