Asked by bill nye
A thin rod 2.4 m long with a mass of 3.45 kg is rotated counterclockwise about an axis through its midpoint. It completes 3.9 revolutions every second. What is the magnitude of its angular momentum?
Answers
Answered by
bobpursley
Moment of Inertia for rod: mL^2 / 12
angular momentum= ml^2/12 * 2PI
you are given m, and length.
angular momentum= ml^2/12 * 2PI
you are given m, and length.
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