Question

A thin rod 2.4 m long with a mass of 3.45 kg is rotated counterclockwise about an axis through its midpoint. It completes 3.9 revolutions every second. What is the magnitude of its angular momentum?

Answer 1

Moment of Inertia for rod: mL^2 / 12
angular momentum= ml^2/12 * 2PI
you are given m, and length.