Asked by Noise
Omar wanted to know if x−5 is a factor of the polynomial p(x)=x3−6x2−x+30. He applied the Factor Theorem and concluded that x−5 is a factor of p(x), as shown in the following work.
Step 1: p(5)=53−6(52)−5+30
Step 2: p(5)=125−150−5+30=0
Step 3: p(5)=0, so the remainder is 0.
Step 4: The remainder is 0, so x−5 is a factor of p(x).
Did Omar make a mistake? If so, in which step does his mistake occur?
Yes, Omar's mistake is in Step 1.
Yes, Omar's mistake is in Step 3.
Yes, Omar's mistake is in Step 2.
Yes, Omar's mistake is in Step 4.
No, Omar did not make any mistakes.
Step 1: p(5)=53−6(52)−5+30
Step 2: p(5)=125−150−5+30=0
Step 3: p(5)=0, so the remainder is 0.
Step 4: The remainder is 0, so x−5 is a factor of p(x).
Did Omar make a mistake? If so, in which step does his mistake occur?
Yes, Omar's mistake is in Step 1.
Yes, Omar's mistake is in Step 3.
Yes, Omar's mistake is in Step 2.
Yes, Omar's mistake is in Step 4.
No, Omar did not make any mistakes.
Answers
Answered by
Reiny
Step 1: p(5)=53−6(52)−5+30 makes no sense
where did those numbers come from?
Step 2: p(5)=125−150−5+30=0
Step 3: p(5)=0, so the remainder is 0.
Step 4: The remainder is 0, so x−5 is a factor of p(x).
those lines were correct.
where did those numbers come from?
Step 2: p(5)=125−150−5+30=0
Step 3: p(5)=0, so the remainder is 0.
Step 4: The remainder is 0, so x−5 is a factor of p(x).
those lines were correct.
Answered by
oobleck
He means 5^3 and 5^2, not 53 and 52
Answered by
VVS
No, Omar did not make any mistakes.
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