Ask a New Question

Question

Solve: log(2 cos(2x)+11)=1 where x e(0, 2pi)
5 years ago

Answers

oobleck
log(2 cos(2x)+11)=1
now recall that 10^(logx) = x. So,
2 cos(2x) + 11 = 10^1
2 cos(2x) = -1
cos(2x) = -1/2
So, what do you think?
5 years ago

Related Questions

Please help - I don't know where to begin. My problem is this: Find the numbers "Y" and "Z" if (1 an... What do you have to do and where do you have to go to get a book published? what are the requiremen... can anyone help me to know where to look for attempts the gov. is doing for health care.doing a powe... Solve the equation for ex, where 0 </x<2pi 2sinx+1=0 Solve the following for x, where 0 < x < 2 pi. 2 cos^2 x + cos x = 1 solve for Z z^3 = -9 where z is a real number solve the following for x, where 0<x<2pi.... 2tanx+ sq rt 12=0 - write the general solution aswel... solve c(x)=x^2-40x+405 where x equals 15 Solve for ALL values of x, where 0<x<2Pi. (should be greater than or equal to) solve for x? if x^2+j16=0 where j=sqrt(-1)
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use