Asked by Lijim
A coin is weighted so that the probability of obtaining a head in a single toss is .4. If the coin is tossed 25 times, what is the probability of obtaining fewer than 10 head? For this problem, I found the mean and standard deviation first. I got 10 for the mean and 2.45 for the standard deviation. Then I used the formula p(x<10) ---> (z<10-10/2.45) = 0. Then I used the table at the back of my textbook and got 0.5000. But my textbooks says my answer is wrong. It says that the correct answer is .4207.
Answers
Answered by
Lijim
I'm confused. How is it .4207 and not .5000?
Answered by
Reiny
what method are you using to find the mean and SD, they can't be right.
Long way:
you want ...
C(25,0) (.4)^0 (.6)^25 + C(25,1)(.4)(.6^24) + .... + C(25,9((.4^9)(.6^16)
=
Long way:
you want ...
C(25,0) (.4)^0 (.6)^25 + C(25,1)(.4)(.6^24) + .... + C(25,9((.4^9)(.6^16)
=
Answered by
Lijim
I used n times p for the mean and the square root of npq for the standard deviation
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