Asked by Katy
I've been working on this a while, and I thought I got it right...until I got to step two. When I tried "veryfying my solution point" The lines didn't intersect at (4,2). I don't know, it's probably a silly little mistake on my part, but I can't get it quite right.
The problem is:
1.a)
{2x-3y=2
{3x- y=10
My solution is:
x=4 and y=2
Then I have to put it into intercept form,y=mx+b. I'm pretty sure that this is where I'm messing up. I can't remember which numbers I'm supposed to plug into the formula. I got both,:
eq.1)y=2x-3 eq.2)y=3x-1, and
eq.1)y=4m+2 eq2)y=4m+2 ( i think this is even farther wrong than the last one)
Any help is appreciated! ^^
Thanks.
The problem is:
1.a)
{2x-3y=2
{3x- y=10
My solution is:
x=4 and y=2
Then I have to put it into intercept form,y=mx+b. I'm pretty sure that this is where I'm messing up. I can't remember which numbers I'm supposed to plug into the formula. I got both,:
eq.1)y=2x-3 eq.2)y=3x-1, and
eq.1)y=4m+2 eq2)y=4m+2 ( i think this is even farther wrong than the last one)
Any help is appreciated! ^^
Thanks.
Answers
Answered by
bobpursley
you solution is correct.
What are you putting into slope intercept form? Both lines that cross at 4,2?
If so, the first line is...
2x-3y=2
-3y=-2x+2
y= 2/3 x -2/3
On the second, 3x-y=10
-y=-3x-10
y=3x+10
I don't know what you are doing.
What are you putting into slope intercept form? Both lines that cross at 4,2?
If so, the first line is...
2x-3y=2
-3y=-2x+2
y= 2/3 x -2/3
On the second, 3x-y=10
-y=-3x-10
y=3x+10
I don't know what you are doing.
Answered by
Katy
thank you oh so very much! <3
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