Asked by #1
Find the set on which h is continuous.
h(x,y)=(5-xy)/(2+x^2 y^2) +ln((5-xy)/(2+x^2 y^2))
h(x,y)=(5-xy)/(2+x^2 y^2) +ln((5-xy)/(2+x^2 y^2))
Answers
Answered by
oobleck
h will be continuous where
no denominator is zero, and ln is defined
(2 + x^2y^2) is always positive, so that is no problem
ln is defined where 5-xy > 0
So, h(x,y) is continuous everywhere except where xy > 5
no denominator is zero, and ln is defined
(2 + x^2y^2) is always positive, so that is no problem
ln is defined where 5-xy > 0
So, h(x,y) is continuous everywhere except where xy > 5
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