A stone of mass 20g is released from a catapult whose rubber has been arched through 4cm. If the force constant of the rubber is 200N/M. Calculate the velocity with which the stone leaves the catapult.

Answer 1

vf^2=vi^2+2a*d but a = force/mass so
vf^2=2*(200/.020) * .04

Answer 2

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Answer 3

I'm sorry, I don't understand what you mean. Can you please clarify your question or provide more information?