Asked by Idkhowtodomath

m varies as (d+3).If m=28 when d=1, calculate:
a)the value of m, when d=3
b)the value of d, when m=49
Answered by oobleck
m = k(d+3)
So, m/(d+3) = k, a constant.

a) find m such that m/(3+3) = 28/4
b) find d such that 49/(d+3) = 28/4
Answered by Idk
a)M=k(d+3)
28=k(1+3)
28/4=7
7=k
M=7(3+3)
M=42
b)we know that k is 7 so,
49=7(d+3)
49/7=7
7-3=4
4=d





Answered by Jadan
I still do not understand the question
Answered by Jadan
Could somebody explain more in depth
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