Question
Given that alpha and bitter are the roots of 2xsquare subtract 6x subtract 1 equal to 0.find the value of 2alpha bitter square plus 2 alpha square bitter plus 2 alpha bitter
Answers
oobleck
alpha and beta are α,β
you have some problem with typing actual math symbols?
2x^2 - 6x - 1 = 0
2αβ^2 + 2α^2β + 2αβ = 2αβ(α+β+1)
The roots are 3±√11
αβ = (3+√11)(3-√11) = 9-11 = -2
α+β = 3+√11 + 3-√11 = 6
Now finish it off
you have some problem with typing actual math symbols?
2x^2 - 6x - 1 = 0
2αβ^2 + 2α^2β + 2αβ = 2αβ(α+β+1)
The roots are 3±√11
αβ = (3+√11)(3-√11) = 9-11 = -2
α+β = 3+√11 + 3-√11 = 6
Now finish it off