Asked by Godstime
Given that alpha and bitter are the roots of 2xsquare subtract 6x subtract 1 equal to 0.find the value of 2alpha bitter square plus 2 alpha square bitter plus 2 alpha bitter
Answers
Answered by
oobleck
alpha and beta are α,β
you have some problem with typing actual math symbols?
2x^2 - 6x - 1 = 0
2αβ^2 + 2α^2β + 2αβ = 2αβ(α+β+1)
The roots are 3±√11
αβ = (3+√11)(3-√11) = 9-11 = -2
α+β = 3+√11 + 3-√11 = 6
Now finish it off
you have some problem with typing actual math symbols?
2x^2 - 6x - 1 = 0
2αβ^2 + 2α^2β + 2αβ = 2αβ(α+β+1)
The roots are 3±√11
αβ = (3+√11)(3-√11) = 9-11 = -2
α+β = 3+√11 + 3-√11 = 6
Now finish it off
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.