AB has slope -2
BC has slope 1/2 = tan 26.565°
So, AB ⊥ BC
If D is on the angle bisector of ABC, then the angle BD makes is 26.565+45 = 71.565°
So the slope of BD is 3
BD is the line y+6 = 3(x-0)
Consider the points P(2,0), A(-4,2), B(0,-6), and C(6,-3). Write an equation of the line that contains the bisector of angle ABC.
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