Asked by Louis

A cylindrical blood vessel is partially blocked by the buildup of plaque. At one point, the plaque decreases the diameter of the vessel by 52.0%. The blood approaching the blocked portion has speed v0. Just as the blood enters the blocked portion of the vessel, what is its speed v, expressed as a multiple of v0?
Answered by R_Scott
to maintain the volumetric flow rate
... the blood must go faster in a narrower vessel

v = v0 * √(1 / .520)
Answered by R_Scott
oops ...

v = v0 * √(1 - .520)
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