Asked by somto
Calculate the hydrogen ion concentration, pH, POH, OH‐ in 0.02 H2SO4?
Answers
Answered by
DrBob222
H2SO4 is a strong acid for the first H^+.
k2 = about 0.12 but you should look that up to make sure. I may not have remembered it correctly.
.............H2SO4 ==> H^+ + HSO4^-
I..............0.02............ 0..........0
C............-0.02...........+0.02...+0.02
E..............0..................0.02.....0.02
.............HSO4^- ==> H^+ + SO4^2-
I..................0.02........0.02......0
C..................-x...........+x.........x
E............0.02-x.........0.02+x......x
k1 = about 0.012 = (H^+)(SO4^-2)/(HSO4^-)
Plug in the E line into the k1 expression and solve for x to give you the concentrations of each specie. The you can do pH, pOH, H^+ and OH^-
k2 = about 0.12 but you should look that up to make sure. I may not have remembered it correctly.
.............H2SO4 ==> H^+ + HSO4^-
I..............0.02............ 0..........0
C............-0.02...........+0.02...+0.02
E..............0..................0.02.....0.02
.............HSO4^- ==> H^+ + SO4^2-
I..................0.02........0.02......0
C..................-x...........+x.........x
E............0.02-x.........0.02+x......x
k1 = about 0.012 = (H^+)(SO4^-2)/(HSO4^-)
Plug in the E line into the k1 expression and solve for x to give you the concentrations of each specie. The you can do pH, pOH, H^+ and OH^-
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.