Asked by confused
                Points on the terminal sides of angles play an important part in the design of arms for robots. Suppose a robot has a straight arm 10 inches long that can rotate about the origin in a coordinate plane. If the robot's hand is located at (10, 0) and then rotates through an angle of −225°, what is the new location of the hand? 
            
            
        Answers
                    Answered by
            Reiny
            
    (10,0) is on the x-axis, so if you rotate -225°, you are going clockwise 225° which is coterminal with 135°, in the 2nd quadrant
the coordinates would be (10cos135°, 10sin135‚
= (10(-cos45), 10 sin45°)
= (10(-√2/2) , 10(√2/2) )
= ( -5√2 , 5√2 )
    
the coordinates would be (10cos135°, 10sin135‚
= (10(-cos45), 10 sin45°)
= (10(-√2/2) , 10(√2/2) )
= ( -5√2 , 5√2 )
                    Answered by
            R_Scott
            
    (10,0) is 10 units from the origin along the x-axis
negative angles are clockwise rotations
... so the terminal angle is a 45º reference angle in Quad II
x = 10 cos(-225º)
y = 10 sin(-225º)
    
negative angles are clockwise rotations
... so the terminal angle is a 45º reference angle in Quad II
x = 10 cos(-225º)
y = 10 sin(-225º)
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