Asked by Anon Math
As x → π, cos x → ?
As x → (π/3)^+, cos x → ?
As x → (π/3)^+, cos x → ?
Answers
Answered by
Anon Math
and this one please <3
As x → 0−, sin x →?
As x → (π/4), sin x → ?
As x → 0−, sin x →?
As x → (π/4), sin x → ?
Answered by
oobleck
well, you know that
cos π = -1
cos π/3 = 1/2
sin 0 = 0
sin π/4 = 1/√2
Since all these function are continuous everywhere, the limits from both sides exist, and are the same. Namely, the function value there.
cos π = -1
cos π/3 = 1/2
sin 0 = 0
sin π/4 = 1/√2
Since all these function are continuous everywhere, the limits from both sides exist, and are the same. Namely, the function value there.
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