Asked by Tulip
A 40.0-mL solution contains 0.035 M barium chloride (BaCl2). What is the minimum concentration of sodium sulfate (Na2SO4) required in the solution to produce a barium sulfate (BaSO4) precipitate? The solubility product for barium sulfate is
Ksp = 1.1 ✕ 10−10.
Ksp = 1.1 ✕ 10−10.
Answers
Answered by
DrBob222
BaSO4 ==> Ba^2+ + [SO4]^2-
Ksp = (Ba^2+) [SO4]^2-
You know Kap and you know (Ba^2+) from the problem. Solve for sulfate ion.concentration in mols/L = M. In this case th 40.0 mL doesn't matter.
Ksp = (Ba^2+) [SO4]^2-
You know Kap and you know (Ba^2+) from the problem. Solve for sulfate ion.concentration in mols/L = M. In this case th 40.0 mL doesn't matter.
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