Asked by Anon
The reaction between nitric oxide (NO) and oxygen to form nitrogen dioxide (NO2) is a key step in photochemical smog formation.
2 NO(g) + O2(g) 2 NO2(g)
(a) How many moles of NO2 are formed by the complete reaction of 0.404 mole of O2?
(b) How many grams of NO2 are formed by the complete reaction of 1.44 g of NO?
2 NO(g) + O2(g) 2 NO2(g)
(a) How many moles of NO2 are formed by the complete reaction of 0.404 mole of O2?
(b) How many grams of NO2 are formed by the complete reaction of 1.44 g of NO?
Answers
Answered by
DrBob222
2NO(g) + O2(g) ==> 2NO2(g)
1. 0.404 mols NO x (2 mols NO2/1 mol O2) = ? mols NO2 formed.
2. mols NO = grams NO/molar mass NO = ?
Convert mols NO to mols NO2 with the coefficients like so.
? mols NO x (2 mols NO2/2 mols NO) = mols NO2 formed.
Then mols NO2 x molar mass NO2 = grams NO2 = ?
Post your work if you get stuck.
1. 0.404 mols NO x (2 mols NO2/1 mol O2) = ? mols NO2 formed.
2. mols NO = grams NO/molar mass NO = ?
Convert mols NO to mols NO2 with the coefficients like so.
? mols NO x (2 mols NO2/2 mols NO) = mols NO2 formed.
Then mols NO2 x molar mass NO2 = grams NO2 = ?
Post your work if you get stuck.
Answered by
Fiona
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