Asked by Anonymous
A motorbike at a constant rate from a standing start. After 1.2s it is travelling 6.0m/s. how much time will have elapsed starting from rest before the bike is moving with a speed of 15m/s
Answers
Answered by
bobpursley
vf=at a= v/t=6/1.2=5m/s^2
t=vf/a=15/5 sec
t=vf/a=15/5 sec
Answered by
henry2,
V = Vo + a*t = 6.
0 + a*1.2 = 6,
a = 5 m/s^2.
V = Vo + a*t = 15.
0 + 5*t = 15,
t =
0 + a*1.2 = 6,
a = 5 m/s^2.
V = Vo + a*t = 15.
0 + 5*t = 15,
t =
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