Question

Please help i have done this problem several times i dont know what is wrong?
After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of v = 3.05 m/s (Figure 10-24). To reach the rack, the ball rolls up a ramp that rises through a vertical distance of h = 0.43 m.
(a) What is the linear speed of the ball when it reaches the top of the ramp?
(I said 1.61 m/s)
(my thought process was)

3.05^2*(.43+1/5)-9.81*0.43=v^2*(.43+1/5)

solve for v , please help

Answer 1

final KE=initilaKE-gaininPE
1/2 m vf^2=1/2m vi^2 - m*9.8*.43 divide thru by 1/2 m
vf^2=vi^2 -2(9.8*.43)
vf^2=3.05^2 -8.43
vf= sqrt(.873) not your answer.

Answer 2

why does your mass change? The ball isn't going at relativistic speeds ...