how can a leg be longer than the hypotenuse?
You figured using 24,26 as legs.
Consider one of your basic Pythagorean triples: 5-12-13, and its multiples
2cm
10cm
35cm**
50cm
You figured using 24,26 as legs.
Consider one of your basic Pythagorean triples: 5-12-13, and its multiples
In this case, we are given the length of the hypotenuse (c = 26 cm) and one leg (a = 24 cm). We need to find the length of the other leg (b).
Using the Pythagorean theorem, we can write the equation as:
c^2 = a^2 + b^2
(26 cm)^2 = (24 cm)^2 + b^2
676 cm^2 = 576 cm^2 + b^2
Subtracting (576 cm^2) from both sides of the equation, we get:
100 cm^2 = b^2
Taking the square root of both sides of the equation, we find:
√(100 cm^2) = √(b^2)
10 cm = b
Therefore, the length of the other leg of the right triangle is 10 cm.
Let's denote the length of the other leg as x cm. According to the problem, the length of the hypotenuse is 26 cm, and the length of one leg is 24 cm.
Using the Pythagorean theorem, we can write the equation:
x^2 + 24^2 = 26^2
Simplifying the equation, we get:
x^2 + 576 = 676
Now we can solve for x by subtracting 576 from both sides of the equation:
x^2 = 676 - 576
x^2 = 100
To find the value of x, we take the square root of both sides:
x = √100
x = 10
Therefore, the length of the other leg is 10 cm.