Asked by Anonymous
In the figure provided, a 119 g ball on a 78.9 cm rope is swung in a vertical circle about a point 249 cm above the ground. If the tension in the rope when the ball is at the very bottom of the circle is 8.80 N and a pair of scissors cuts the string directly below the point of support, how far to the right of where the string was cut does the ball hit the floor?
Answers
Answered by
bobpursley
time to fall vertically: t=sqrt(2h/9.8)=sqrt(2*(2.49-.789)/9.8)=... do that
velocity at bottom:
a=v^2/r or
v=sqrt(a*r)=sqrt(8.8*.789)
distance traveled in falling= v*t
velocity at bottom:
a=v^2/r or
v=sqrt(a*r)=sqrt(8.8*.789)
distance traveled in falling= v*t
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