Asked by Sandeep Kumar

Find the range of all possible values of B if the graph of
P(x) = 12x⁴ - 5x³ -38x² + Bx + 6
crosses the x-axis between 0 and -1
Answered by oobleck
12x^4 - 5x^3 - 38x^2 + 0x + 6 = 0
P(0) = 6
P(-1) = -B-15
So, B > -15
Answered by Sandeep Kumar
Could you explain what you did in the first and the last line of your comment?
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