Asked by Sandeep Kumar

Find the range of all possible values of B if the graph of
P(x) = 12x⁴ - 5x³ -38x² + Bx + 6
crosses the x-axis between 0 and -1

Answers

Answered by oobleck
12x^4 - 5x^3 - 38x^2 + 0x + 6 = 0
P(0) = 6
P(-1) = -B-15
So, B > -15
Answered by Sandeep Kumar
Could you explain what you did in the first and the last line of your comment?
There are no AI answers yet. The ability to request AI answers is coming soon!